WAEC EXPO 2018; 2018 WAEC PHYSICS PRACTICAL EXPO ANSWER RUNS | WAEC EXPO 2018/2019 FREE WAEC PHYSICS PRACTICAL EXPO ANSWERS 2018/2019 (1a) TABULATE: S/N: 1, 2 , 3, 4, 5 L(cm): 90.00, 80.00, 70.00, 60.00, 50.00 T(s): 38.00, 36.00, 34.00, 31.00, 28.00 T = t/20(sqt): 1.90, 1.80, 1.70, 1.55, 1.40 √L(cm^1/2): 9.49, 8.94, 8.37, 7.73, 7.07 (1aix) Slope(s) = Δvertical/Δhorizontal =1.90 – 1.55/9.49 – 7.75 = 0.35/1.74 S = 0.201 (1ax) g = 4π²/S² = 4 ×(3.142)²/(0.201)² = 977.4cm/s² (1axi) (i) I ensured the angle of oscillation is relatively small. (ii) I ensured that no external force is added to the system of oscillation. (iii) I ensured the oscillation is perfect (2ai) fo=15cm 2av) a=60.00cm b=20.00cm Hence L=a/b=60.00/20.00 L=3 (2avi) TABULATE S/N:1,2,3,4,5 b(cm):20.00,25.00,35.00,40.00 a(cm):60.00,37.50,30.00,26.25,24.00 L=a/b:3.00,1.50,1.00,0.75,0.60 2avii) Slope=Change in L/Change in a =(3-0.25)/(60-18.6) =2.75/41.4 =0.006642 2aviii) S^-1=1/S ...
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